Math, asked by rambhakt67, 3 months ago

a) Write a Pythagorean triplet whose one member is 6.

b) Express 49 as the sum of 7 odd numbers.

c) How many numbers lie between squares of 99 and 100?

Answers

Answered by Anonymous

2

Answer:

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Answered by heer112

1

Answer:

a. 6,8,10 b. 1+3+5+7+9+11+13 c. 199

Step-by-step explanation:

a. 6^2 =36, 8^2=64 so according to pythagoras theorem 36+64=100 so 10^2 so answer will be 6,8,10

c. 100^2=10000 and 99^2=9801 sp. 10000-9801= 199

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