a) Write a Pythagorean triplet whose one member is 6.
b) Express 49 as the sum of 7 odd numbers.
c) How many numbers lie between squares of 99 and 100?
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Answered by
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Answer:
a. 6,8,10 b. 1+3+5+7+9+11+13 c. 199
Step-by-step explanation:
a. 6^2 =36, 8^2=64 so according to pythagoras theorem 36+64=100 so 10^2 so answer will be 6,8,10
c. 100^2=10000 and 99^2=9801 sp. 10000-9801= 199
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