Question

(a) Write a two digit number with sum of its digits 9
(b) The sum of the digits of a two de b er is 9. The number got by
the digits is 27 more than the onenal number. What is the number?
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Answer 1

Answer:

36

Step-by-step explanation:

Let units digit is x and tens digit is y.

x+y=9

The no. is 10y+x

On reversing we get 10x+y

Now 10y+x+27=10x+y

9x-9y=27

x-y=3

Solving two equation we get x=6 and y=3

So no. is 36

Answer 2

Answer:

Let the digits at tens place and ones place: x and 9−x respectively.

∴ original number =10x+(9−x)

=9x+9

Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively.

∴ New number: 10(9−x)+x

=90−10x+x

=90−9x

AS per the question

New number = Original number +27

90−9x=9x+9+27

90−9x=9x+36

18x=54

x=

18

54

x=3

Digit at tens place ⇒3 and one's place : 6

∴ Two digit number: 36