Question

a) Write an arithmetic sequence with first term 9 and common difference 8 .
b) What is the 16th term of this sequence ?

Answer 1

Answer:

(a) 9,17,25,33,41,49,57,65,73 and so on

(b)an=a+n-1

a16=9+n-1

a=146

Answer 2

The value of the 16th term is 129.

Step-by-step explanation:

Given:

The first number, a= 9

and common difference; d= 8

Solution:

We need to write the sequence:

So, using the formula, $a_{n}$= a+(n-1)d

$a_{2}$=   9+(2-1)8

$a_{2}$= 9+8= 17

now, $a_{3}$= 9+(3-1)8

$a_{3}$= 9+16= 25

Thus, the sequence becomes 9,17,25....

Now, 16th term:

$a_{16}$= a+(16-1)d

$a_{16}$= 9+15×8

$a_{16}$= 9+ 120

$a_{16}$= 129

Result:

Thus, the value of the 16th term is 129.

(#SPJ3)