a) Write an arithmetic sequence with first term 9 and common difference 8
b) What is the 16th term of this sequence ?
Answers
Answered by
1
Answer:
9,17,25,33
an=9+(16-1)8
=9+120
=129
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Answered by
0
Answer:
Given: first term,a = 9
common difference ,d = 8
a2= a+ d=9+8=17
a3= a + 2d = 9+2(8)= 25
a4= a + 3d = 9 +3(8)= 33
b) 16th term,
a16= a + 16d = 9+ 16(8) = 137
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