Question

a) Write the chemical equations when dil, mod, conc, HNO3 reacts
with ‘Cu’
b) Define the term Oxidation

Answer 1

Answer:

Nitric acid reacts with copper according to the reaction: 4 HNO3(l) + Cu(s) ==> Cu(NO3)2(s and aq) + 2 NO2(g) + 2 H2O(l) The copper nitrate salt that forms is a deep blue color

Oxidation is loss of electrons (OIL RIG). That means that an oxidising agent takes electrons from that other substance. So an oxidising agent must gain electrons.

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Answer 2

Different chemical reactions are formed when dil and conc. HNO3 reacts with CU

• Cu is copper, so we have to write chemical equations for reaction with copper.
• When dil HNO3 reacts with copper, equation is :
• 3Cu + 8HNO$_{3}$ →  $(CuNo_{3} )_{2}$ + 2NO + 4$H_{2}$O
• Nitric oxide, water, and copper nitrate are produced in these reactions when copper metal reacts with diluted nitric acid.
• When conc. HNO3 reacts with copper, equation is :
• Cu+4HNO$_{3}$ → Cu(NO$_{3}$)$_{2}$+2NO$_{2}$+2H$_{2}$O
• An inorganic substance called cupric acid crystallises as a dark-blue solid. In a vacuum, anhydrous copper nitrate crystallises into vivid blue-green crystals. There are five different hydrates of it as well. Copper nitrate is primarily used to create copper oxide, which is then employed as a catalyst in a variety of processes.
• A molecule, atom, or ion undergoes oxidation when it loses electrons as a result of a process.
• When a molecule, atom, or ion's oxidation state is raised, oxidation takes place. When there is an increase in electrons or a drop in an atom, molecule, or ion's oxidation state, the process is known as reduction.

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