Question

a)Write the equation in ionic form
CUS04 (aq)+ Fe (s) —> FeSO4 (aq) + Cu (s)

Divide the above equation into oxidation and reduction half reactions

Answer 1

Answer:

1)The net ionic equation is:  

Cu+2(aq) + Fe(s) --> Fe+2(aq) + Cu(s)  

Any spectator ions are canceled out in a net ionic equation - those that do not take part in the reaction. In this case the sulfate ion (SO4-2). It is common on both sides of the reaction to balance the charge and plays no role other than to form ionic compounds with the Cu+2 and Fe+2 ions.

​​​​2) ​​​​Overall reaction: {Fe + CuSO4 → FeSO4 + Cu

Oxidation of iron: {Fe → Fe2+ + 2 e-

Reduction of copper: {Cu2+ + 2 e- → Cu

SO4 2- is a “spectator ion”

Electrons released by iron are taken up by copper: a “redox couple”

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Answer 2

Explanation:

Here's your answer

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#Reduction : Copper sulphate is reduced to Copper...

#Oxidation : Iron is oxidised into iron sulphate...

Hope it helps ✌