Question

a) Write the general electronic configuration of transition elements and inner transition elements

b) Explain the following
i. electron affinity of chlorine is more than of fluorine.
ii. I.E of nitrogen is greater than that of oxygen.

please give correct and acceptable answer i need it for project

Answer 1

✔In general the electronic configuration of these elements is (n-1)d1–10 ns1–2. The (n–1) stands for the inner d orbitals which may have one to ten electrons and the outermost ns orbital may have one or two electrons. 

✅ 1.Fluorine, though higher than chlorine in the periodic table, has a very small atomic size. This makes the fluoride anion so formed unstable (highly reactive) due to a very high charge/mass ratio. ... As a result, fluorine has an electron affinity less than that ofchlorine.

2.Oxygen has low ionisation energy (than that ofnitrogen). It is due to an electron being added to an already half full orbital in oxygen, which results in electron electron repulsion, which will lower theionisation energy

Answer 2

General e configuration of

Transition elements :-

(n-1)d1–10 ns1–2.

B)

1. E affinity decreases from left to right & increases in group . Therefore cl E affinity is gr8ter than f.

2. Ionisation energy

Oxygen has low ionisation energy (than that ofnitrogen). It is due to an electron being added to an already half full orbital in oxygen, which results in electron electron repulsion, which will lower the ionisation energy.

I hope it helps u .