Question

a) Write the ionic equation for the reaction between zinc powder and tetraoxosulphate (vi) acid solution.
b) which substance in (a) is oxidized (ii) reduced

Answer 1

ANSWER

n(s) + H2SO4 --> ZnSO4(aq) + H2(g)

Zn(s) + 2H+ --> Zn2+ + H2(g)

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Answer 2

Answer:

Tetraoxosulphate(vi) acid solution is commonly known as Sulphuric Acid (H₂SO₄). Therefore, the ionic equation for reaction between Zinc and Suplhuric Acid is :

                 Zn + 2H⁺ + SO₄²⁻ → Zn²⁺ + SO₄²⁻ + H₂

The substance oxidized is Zn from Zn to Zn²⁺.

The substance reduced is H⁺ from 2H⁺ to H₂.

Explanation:

Similar to a molecular equation, which expresses compounds as molecules, an ionic equation is a chemical equation wherein the electrolytes in aqueous solution are expressed as dissociated ions. Usually, this is a salt dissolved in water, in which the ionic species are accompanied via way of means of (aq) withinside the equation to signify they're in aqueous solution.

The ions in aqueous solutions are stabilized via way of means of ion-dipole interactions with water molecules. However, an ionic equation can be written for any electrolyte that dissociates and reacts in a polar solvent. In a balanced ionic equation, the quantity and kind of atoms are the identical on each aspects of the response arrow. Additionally, the net charge is the identical on each aspects of the equation.

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