Question

a) Write the sequence got by adding one to the square of consecutive natural numbers starting from 1
b) What is the 10th term of this sequence? c) Write the algebraic form of this sequence?

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Answer 1

Answer:

1+2+9+16+25+36+49+64+81+100

Answer 2

Answer:

Given : sequence got by adding 1 to the square of consecutive natural numbers starting from 1​

To Find :  the sequence

10th term of this sequence

the algebraic form of this sequence

Solution:

adding 1 to the square of consecutive natural numbers starting from 1​

Tₙ = n² + 1

n = 1

=> T₁= 1² + 1  = 2

n = 2

=> T₂= 2² + 1  = 5

n = 3

=> T₃= 3² + 1  = 10

n = 4

=> T₄= 4² + 1  = 17

n = 5

=> T₅= 5² + 1  = 26

n = 6

=> T₆= 6² + 1  = 37

Hence sequence is

2 ,  5  , 10 , 17  ,  26 , 37  and so on

Tₙ = n² + 1

n = 10

=> T₁₀ = 10² + 1  = 101

the algebraic form of this sequence   n² + 1    n∈ natural numbers

Step-by-step explanation:

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