Question

a) Write three consecutive multiples of 5 ?

b) If x is the smallest number in three consecutive multiples of 5 ,which are the other

numbers ?

c) If the sum of three consecutive multiples of 5 is 135 , find the numbers ?
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Answer 1

a ) the consecutive integers, multiple of 5, are: 35 ; 40 ; 45.

b) 40 and 45

c) find that that the smallest number be x

equation is

x+(x+5)+(x+10)=135

3x+15 =135

3x= 120

x= 120/3

x= 40

hence the first consecutive number is 40

the second consecutive number is x + 5 means 40 plus 5 equals to 45

and the last third consecutive number is X + 10 means 40 + 10 which is equals to 50

I wrote this much for you please mark the answer as brainlist

Answer 2

Answer:

1) 35 , 40 , 45

2) 5×1=5 , 5×2=10 , 5×3=15

3)5(x)+5(x+1)+5(x+2)= 135

Step-by-step explanation:

Hope it helps you