Math, asked by Vaishnav2724, 8 months ago

A=x^1/3.y^1/3+x^(-1/3).y^(-1/3) find a^3-3ay-x=?(A) y/x(B)x/y(C)x^2/y(D)y^2/x

Answers

Answered by xxxitzCottonCandyxxx
1

Question:

9=×^1/3.y^1/3+×^(-1/3).y^(-1/3) find a^3-3ay-×=

solution is in the attachment

here in this question we have to assume the value of × & y.

I have assume ×=8 & y = 1

solution is = A3 - 3ay - × =

0.125 = 125/1000 = 1/8

Answered by khushi962682
1

Answer:

  \frac{125}{100}  \\  \\  \\  \\  \frac{1}{8}

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