Question

((a ^ (x + 1))/(a ^ (y + 1))) ^ (x + y) * ((a ^ (y + 2))/(a ^ (z + 2))) ^ (y + z) * ((a ^ (z + 3))/(a ^ (x + 3))) ^ (z + x) = 1​

Answer 1

Answer:

=[a^(x+1)-(y+1)]^(x+y)*[a^(y+2)-(z+2)]^(y+z)*[a^(z+3)-(x+3)]^z+x

=(a^x+1-y-1)^(x+y)*(a^y+2-z-2)^(y+z)*(a^z+3-x-3)^(z+x)

=a^(x-y)(x+y)*a^(y-z)(y+z)*a^(z-x)(z+x)

$a ^(x ^ {2} - {y}^{2} + {y}^{2} - {z}^{2} + {z}^{2} - {x}^{2} )$

= a^0=1

hence proved

Step-by-step explanation:

=we just gave to put up exponent rules.

= if you want whya^0 =1:

= a^0 can be written as a^1-1=a^1/a^1.=1