(a^x+1/a^y+1)^x+y (a^y+2/a^z+2)^y+z (a^z+3/a^x+3)^z+x = 1
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Answered by
0
Answer:
1
Step-by-step explanation:
(
a
y+1
a
x+1
)
x+y
(
a
z+2
a
y+2
)
y+z
(
a
x+3
a
z+3
)
z+x
=a
(x−y)(x+y)
a
(y−z)(y+z)
a
(z−x)(x+z)
=a
(x−y)(x+y)+(y−z)(y+z)+(z−x)(z+x)
=a
0
=1
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