Question

(a-x)^2 (a+x)^2 pls solve this !!
​

Answer 1

Answer:

Answer:

x = -a, a/2

Step-by-step explanation:

\begin{gathered}2 {x}^{2} + ax - {a}^{2} = 0 \\ = > 2 {x}^{2} + 2ax - ax - {a}^{2} = 0 \\ = > 2x(x + a) - a(x + a) = 0 \\ = > (2x - a)(x + a) = 0 \\ \\ for \: (x + a) = 0 \\ = > x = - a \\ \\ for \: (2x - a) = 0 \\ = > 2x = a \\ = > x = \frac{a}{2} \end{gathered}

2x

2

+ax−a

2

=0

=>2x

2

+2ax−ax−a

2

=0

=>2x(x+a)−a(x+a)=0

=>(2x−a)(x+a)=0

for(x+a)=0

=>x=−a

Answer 2

Answer:

2a^2 + 2x^2

Explanation:

(a-x)^2 = a^2 - 2ax + x^2

(a+x)^2 = a^2 + 2ax + x^2

(a-x)^2 + (a+x)^2

= (a^2 - 2ax + x^2) + (a^2 + 2ax + x^2)

= a^2 + a^2 + x^2 + x^2

= 2a^2 + 2x^2