a = x^2. Find v at x = 2 m if at x = 0 body is at rest.
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Acceleration and displacement are related as a = x? we know, acceleration , a = v so, x? = v →x?dx = vdv - Sx?dx = [vdv dv dx dv dx at x = 0, body is in rest . initial velocity, Vo = 0 Let velocity at x = 2 is v 2 V Now, fx? dx= [v dv X' - [x°/3]%, = \bf{\frac{v^2}{2}}^\V_O → 8/3 = v?/2 16/3 = v? So, v = +4/v3 m/s Hence, magnitude of velocity = 4//3 m/s abhi178 •
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