Question

(a) x :3::12:4

(b) 5:x::15:60​

Answer 1

Let the number of cows be x and their legs be 4x.

Let the number of chicken be y and their legs be 2x.

Total number of legs = 4x + 2y.

Total number of heads = x + y.

The number of legs was 14 more than twice the number of heads.

Therefore, 2 × (x + y) + 14 = 4x + 2y.

or, 2x + 2y + 14 = 4x + 2y.

or, 2x + 14 = 4x [subtracting 2y from both sides].

or, 14 = 4x – 2x [subtracting 2x from both sides].

or, 14 = 2x.

or, x = 7 [dividing by 2 on both sides].

Therefore, the number of cows = 7.

Answer: (b)

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Answer 2

(a) x : 3 :: 12 : 4

Product of mean = Product of extreme

=>X x 4 = 3 x 12

=>X x 4 = 36

=>X = 36/4

=>X = 9

Therefore X =9

(b) 5:X :: 15 : 60

Product of extreme = Product of mean

=> 5 x 60 = X x 15

=> 300 = X x 15

=> 300/15 = X

=> 20 = X

Therefore X = 20

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