Question

(a) (x-3) (x+1) = 1/2 x=?​

Answer 1

Step-by-step explanation:

$(x - 3)(x + 1) = \frac{1}{2} \\ \leadsto{x}^{2} + x - 3x - 3 = \frac{1}{2} \\ \leadsto {x}^{2} - 2x - 3 - \frac{1}{2} = 0 \\ \\ \leadsto \frac{2 {x}^{2} - 4x - 6 - 1}{2} = 0 \\ \leadsto \bold{2 {x}^{2} - 4x - 7} \\ \\ \bold{Using \: Quadratic \: formula \: for \: finding \: x} \\ \\ \fbox{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} } \\ \\ Here, \\ \bold{a = 2 }\\ \bold{b = - 4} \\ \bold{ c = - 7} \\ \\ x = \frac{ - \bold{( - 4)} \pm \sqrt{ \bold{( - 4) {}^{2}} - 4 \times \bold{2} \times \bold{( - 7)}} }{2 \bold{(2)}} \\ \\ x = \frac{4 \pm \sqrt{16 + 56} }{4} \\ x = \frac{4 \pm \sqrt{72} }{4} \\ \\ Hence, \\ \bold{the \: value \: of \: x = } \\ \\ \fbox{ x = \frac{4 \pm \sqrt{72} }{4} } \: \: \bold{or} \: \: \fbox{x = \frac{4 \pm6 \sqrt{2} }{4} }$

Answer 2

Answer:

Answer

Step-by-step explanation:

Here is your answer

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