A = {x|3x + 1 = 13); B=(x|x is a perfect square between 3 and 8) C= {x|x is an element of set N, 3 <x<8}
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A={x:x is a perfect square,x<50,x∈N}
∴A={1,4,9,16,25,36,49}
B={x:x=8m+1, where m∈W,x<50,x∈N}
∴B={1,9,17,25,33,41,49}
Therefore,
A∩B={1,9.25,49}
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