Question

a.
x + 4
3x - 8
2. Find the solution set of the inequation
5
<
if the replacement set is
3
b. I
c. W
a. N​

Answer 1

Step-by-step explanation:

We have,

$\frac{3x - 8}{5} \leqslant \frac{x + 4}{3}$

$\implies9x - 24 \leqslant 5x + 20$

$\implies4x \leqslant 44$

$\implies \: x \leqslant 11$

$x \in ( - \infty , 11]$