A(X,
4. Find all possible values of y for which the distance between the points
A(2, -3) and B(10, y) is 10 units.
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2
Answer:
3, -9
Step-by-step explanation:
AB = 10
Squaring both sides
AB² = 10²
(√[(10-2)²+(y-(-3))²])² = 100
8²+(y+3)² = 100
( y+3)² = 100-64
y+3 = ± √36
y+3 =± 6
if y +3 = 6
then y = 6-3 = 3
if y +3= -6
then y = -6-3 = -9
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