Math, asked by atulanand91, 11 months ago

a/x-a+b/x-a = c/x-c​

Answers

Answered by sshh1630
0

Answer:

Step-by-step explanation:

a/x - a+b/x-a = c/ x-c

ax- a^2 - ax- bx/ x^2 - ax= c/ x-c {taking LCM}

-a^2- bx/ x^2- ax= c/x-c

(-a^2- bx)(x-c)= (x^2- ax)(c)

-a^2x+ a^c- bx^2+ bcx= cx^2- ac^2

- bx^2- cx^2-a^2x+ bcx+ a^c+ ac^2= 0

bx^2 + cx^2 + a^2x- bcx - a^c- ac^2=0

(b+c)x^2 + (a^2-b)x - a^c- ac^2=0

d= b^-4ac

= (a^2- bc)^2 -4* (b+c)* (-a^c- ac^2)

a^4 + b^2c^2- 2a^2bc- 4(-ba^2c- bac^2- a^2c^2- ac^3)

a^4 + b^2c^2- 2a^2bc + 4a^2bc+ 4abc^2 + 4a^2c^2+ 4ac^3

a^4 + b^2c^2+ 2a^2bc+ 4abc^2 + 4a^2c^2+ 4ac^3

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