Question

(a+x+√(a²+x²))/(a+x-√(a²+x²))

Answer 1

Step-by-step explanation:

∫√(a²+x²)dx = (1/2) x√(a²+x²) + (1/2) a²log |x+ √(a²+x²)| +C

∫√(a²-x²) = (1/2) x√(a²-x²) + (1/2) a²sin-1(x/a) + C

∫√(x²-a²) = (1/2) x√(x²-a²)- (1/2) a²log | x+ √ ( x² - a² ) | +C

Answer 2

Answer:

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