a/x-b +b/x-a =2 solve equation
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{a(x-a) +b(x-b)} /(x-a) (x-b) =2
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Answer:
a x + b x - 2 ab = (x - a)² + (x - b)²
Step-by-step explanation:
Given equation,
a/x-b +b/x-a =2
Take L.C.M of (x-b) and (x-a)
{a(x-a) +b(x-b)} /(x-a) (x-b) = 2
(a x - a² + b x - b²)/(x-a) (x-b) = 2
(a x - a² + b x - b²) = 2 (x-a) (x-b)
(a x - a² + b x - b²) = 2 (x² - a x -b x + ab)
(a x - a² + b x - b²) = 2 x² - 2 a x - 2 b x + 2 ab
a x + b x - 2 ab = (x² - 2 a x + a²) + (x² - 2 b x + b²)
a x + b x - 2 ab = (x - a)² + (x - b)²
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