a^x = b , b^y = c , c^z = a.
Prove that xyz = 1
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ax=b => x=logab
ax=b => x=logabby=c=> y=logbc
ax=b => x=logabby=c=> y=logbccz=a=> z=logca
ax=b => x=logabby=c=> y=logbccz=a=> z=logcaxyz=(logab.logbc).logca
ax=b => x=logabby=c=> y=logbccz=a=> z=logcaxyz=(logab.logbc).logca=logac.logca
ax=b => x=logabby=c=> y=logbccz=a=> z=logcaxyz=(logab.logbc).logca=logac.logca=logaa
ax=b => x=logabby=c=> y=logbccz=a=> z=logcaxyz=(logab.logbc).logca=logac.logca=logaa=1
ax=b => x=logabby=c=> y=logbccz=a=> z=logcaxyz=(logab.logbc).logca=logac.logca=logaa=1Thanks & Regards
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