Question

a^x=b,b^y=c,c^z=a then find x^2 y^2 z^2

Answer 1

Your answer is --

Given,

➡ a^x = b

=> b^y = (a^x)^y

=> b^y = a^xy

Also, given

b^y = c

So,

c = a^xy

=> c = (c^z)^xy [ given, a = c^z ]

=> c = c^xyz

we know that when base are some ,power are also same .

So,

➡ xyz = 1

Therefore,

x^2y^2z^2 = (xyz)^2

= 1^2 = 1

Hence, [ x^2y^2z^2 = 1 ]


【 Hope it helps you 】