a^x=b,b^y=c,c^z=d, prove xyz=1
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Hi friend,
We know that, a^x = N then x = log^N a
a^x=b
=> x=log^b a
b^y=c
=> y=log^c b
c^z=a
=> z=log^a c
We have to prove that xyz = 1,
→ Proof:-
=> xyz = (log^b a) (log^c b) (log^a c)
= log^c a × log^a c
= log^a a
= 1
Hence proved.
>>>>>>>>>>>>>>>>>>>>>>>>>>>
Hope it helps
We know that, a^x = N then x = log^N a
a^x=b
=> x=log^b a
b^y=c
=> y=log^c b
c^z=a
=> z=log^a c
We have to prove that xyz = 1,
→ Proof:-
=> xyz = (log^b a) (log^c b) (log^a c)
= log^c a × log^a c
= log^a a
= 1
Hence proved.
>>>>>>>>>>>>>>>>>>>>>>>>>>>
Hope it helps
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