Math, asked by summaiyakousar, 1 year ago

(a-x)(b-x)(c-x)(d-x)..........(z-x)=?
the simplest way to answer is?


summaiyakousar: yes
summaiyakousar: from (a-x) to (z-x)
summaiyakousar: its so easy you just need to know the logic

Answers

Answered by mrambabu1600
23
at the end we have x-x
the value of x-x is 0
any thing multiplied by 0 is 0
hence (a-x)(b-x)(c-x)....(y-x)(z-x)=0

summaiyakousar: yes your answer is correct
Answered by hotelcalifornia
10

Answer:

( a - x ) ( b - x ) ( c - x ) ( d - x ) \dots \ldots \ldots ( z - x ) = 0

Solution:

Given that

\begin{array} { l } { ( a - x ) ( b - x ) ( c - x ) ( d - x ) \ldots \ldots \ldots ( z - x ) = ? } \\\\ { ( a - x ) ( b - x ) ( c - x ) ( d - x ) ( e - x ) ( f - x ) \dots \ldots ( u - x ) ( v - x ) ( w - x ) ( x - x ) ( y - x ) ( z - x ) } \end{array}

Here the value of

x-x=0

Hence the total expression is equals to zero.

(a-x)(b-x)(c-x)(d-x)(e-x)(f-x)\dots \dots \dots (u-x)(v-x)(w-x)(0)(y-x)(z-x)\\\\(a-x)(b-x)(c-x)(d-x)(e-x)(f-x)\dots \dots \dots \times 0\\\\0=0.

Hence, the whole expression will be 0.

( a - x ) ( b - x ) ( c - x ) ( d - x ) \dots \ldots \ldots ( z - x ) = 0

Hence the answer is 0.

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