Question

a/x - b/y = 0 , ab^2 / x + a^2b/y=(a^2 + b^2)

answer will get 49 points

Answer 1

Answer:

hope it helps you...........

Answer 2

☺️solution☺️

$value \: of \: x \: = a \: and \: y = b$

$given \: system \: of \: equation$

$\frac{a}{x} - \frac{b}{y} = 0 \: ............equation \: 1$

$\frac{ab {}^{2} }{x} + \frac{a {}^{2}b }{y} = {a}^{2} + {b}^{2} \:...........2$

$given \: equation \: are \: not \: linear$

$let \: \frac{1}{x} = u \: and \: \frac{1}{y} = v$

$we \: get$

$au \: - \: bv = 0..............3$

${ab}^{2}u + {a}^{2}bv = {a}^{2} + {b}^{2} ..........4$

$from \: equation \: 3$

$v = \frac{bv}{a}$

$put \: this \: in \: eqn \: 4$

${ab}^{2} \times \frac{bv}{a} + {a}^{2} bv = {a}^{2} + {b}^{2}$

$b3v + {a}^{2} bv = {a}^{2} + {b}^{2}$

$( {b}^{2} + {a}^{2} )bv = {a}^{2} + {b}^{2}$

$v = \frac{1}{b}$

$u = b \times \frac{1}{b} = \frac{1}{a}$

$so$

$\frac{1}{x} = \frac{1}{a \: }$

$then \: x = a \: and \: \frac{1}{y} = \frac{1}{b}$

$y = b$

$therefore \: value \: of \: x = a \: \: and \: y = b$

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$mark \: me \: as \: \:a \: brainlist \: please$