Math, asked by sachdevasanya83, 10 months ago

a/x - b/y=0
ab²/x + a²b/y =a²+b²​

Answers

Answered by sriram12345mass007
1

a/x \ b/y=0

ab//2 x + ab b/= a+ b

Answered by rahulnarayana2
2

Answer:

Step-by-step explanation:

The given equations are

ax−by=0 ........... (i)

ab2x+a2by=(a2+b2) ........... (ii)

Put 1x= u and 1y= v in the  equation (i) and (ii),

we get  ⇒au−bv=0 .............(iii)

ab2u+a2bv−(a2+b2)=0......(iv)

So, by cross multiplication,

ub1c2−b2c1=vc1a2−c2a1=1a1b2−a2b1

⇒u(−b)[−(a2+b2)]−(a2b)(0)=v(0)(a2b)−[−(a2+b2)](a)=1(a)(a2b)−(a2b)(−b)

⇒ub(a2+b2)=va(a2+b2)=1ab(a2+b2)

ub(a2+b2)=1ab(a2+b2)

⇒u=1a

and va(a2+b2)=1ab(a2+b2)

⇒v=1b

If u=1a

⇒ x=a

v=1b

⇒ y=b

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