Math, asked by sourajabanerjeehcs, 9 days ago

a^x+b^y=a+b,a^x-1+b^y-1=2 solve for x and y

Answers

Answered by srijannaiya

1

Step-by-step explanation:

x=1

y=1

a^1+b^1=a+b

a^0 +b^0=1+1=2

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