Question

a^x=b^y=c^z and b^2=ac show that y =2zx/2+x​

Answer 1

Step-by-step explanation:

a^x=b^y

a=b^y/x

c^z=b^y

c=b^y/z

b^2= ac

b^2= b^y/x × b^y/z

b^2=. b^(y/x+y/z)

2= y/x+y/z

2=y(x+z/xz)

2xz/x+z = y

hence proved