a x + b y ka whole square + b x minus a y ka whole square
Answers
Answered by
179
Factorise :-
(ax + by)² + (bx - ay)²
Let's open the brackets first
We know that, (a + b)² = a² + b² + 2ab
=> (ax + by)² + (bx - ay)²
= a²x² + b²y² + 2axby + b²x² + a²y² - 2bxay
=> a²x² + a²y² + b²y² + b²x² + 2abxy - 2abxy
(rearranging the terms)
=> a²x² + a²y² + b²y² + b²x²
=> a²(x² + y²) + b²(x² + y²)
=> (a² + b²)(x² + y²)
Hope it helps dear friend ☺️✌️
(ax + by)² + (bx - ay)²
Let's open the brackets first
We know that, (a + b)² = a² + b² + 2ab
=> (ax + by)² + (bx - ay)²
= a²x² + b²y² + 2axby + b²x² + a²y² - 2bxay
=> a²x² + a²y² + b²y² + b²x² + 2abxy - 2abxy
(rearranging the terms)
=> a²x² + a²y² + b²y² + b²x²
=> a²(x² + y²) + b²(x² + y²)
=> (a² + b²)(x² + y²)
Hope it helps dear friend ☺️✌️
Answered by
17
Answer:
Step-by-step explanation:
As we know :-( a+b )^2 =a^2+b^2+2ab
So that
(ax+by)^2+(bx-ay)^2
=ax^2+by^2+2axby +bx^2-2 bxay+ay^2
So we can cancel 2axby and -2bxay
=a^2x^2+ b^2y^2
=a (x^2+y^2)+b (y^2+x^2)
=(x^2+y^2) (a^2+b^2)
Thanks
I hope it helps you
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