Question

A x cm. B 4) ABCD is a trapezium AB || CD AQABCD) =33cm2 Find the lengths of all sides of ABCD + (x - 2)cm. (x - 4)cm D C M k (2x + 1)cm. ㅖ​

Answer 1

Step-by-step explanation:

Given:

ABCD is a trapezium and also given that AB || CD.

A(

◻

ABCD) = `1/2("AB" + "CD") xx "AM"`

33=12(x+2x+1)×(x-4)

∴ 3x(x - 7) + 10(x - 7) = 0

∴ (3x + 10)(x - 7) = 0

∴ 3x + 10 = 0 or x - 7 = 0

∴ x =

-103 or x = 7

But length is never negative.

∴ x = 7

AB = 7cm, CD = 15 cm, AD = BC = 5 cm