a^x logbase e a value is
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Answered by
1
log base a value is 1
Anonymous:
how?
Answered by
0
Hey there,
=>a^(x log base e a)=a^(log base e a^x)
=x
Hope it helps
=>a^(x log base e a)=a^(log base e a^x)
=x
Hope it helps
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