a x square plus two a square x + b cube is exactly divisible by X + a then prove that is equals to B or a square + b + b square is equals to zero
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f(1) and f(−a) both are equal to 0 by factor theorem.
∴ f(1)=1+2+a+b=0 and f(−a)=−a
3
+2a
2
−a
2
+b=0
∴ a+b=−3 and −a
3
+a
2
+b=0
Thus, on solving two equations we get, a=−1 and b=−2
this is your answer.
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