Question

A={x:x is a multiple of 3 and x greater than or equal's to 20}. B={y:y is a factor of 18}.Show that (A union B) -(A intersection B)=(A-B) union (B-A).​

Answer 1

ANSWER:-------

A={x:x is a prime factor of 30}

{we will find all the prime factors of 30 and include them in set A}

[NOTE]={∴A={1,2,3,5,6,10,15,30}

[similarly for set B]

B={1,2,3,4,6,8,12,24}

A∪B={1,2,3,4,5,6,8,10,12,15,24,30}

{union is all the components of 2 or more sets and writing the common components 1 time}

A∩B={1,2,3}

HOPE IT HELPS:----

MARK AS BRAIN LIST:-----

T!—!ANKS!!!

Answer 2

A = { 3,6,9,12,15,18}

B = { 2,3 }

L. H. S. = ( A ∪ B ) - ( A ∩ B )

= { 2, 3, 6, 9, 12,15, 18} - { 3 }

= {2, 6, 9, 12,15, 18}

R. H. S. = ( A - B ) ∪ ( B - A)

= {2, 6, 9, 12,15, 18} ∪ { 2 }

= {2, 6, 9, 12,15, 18}

So, L. H. S. = R. H. S.

Hence, Proved.