A= {x:x is a multiple of 3, x is greater than or equal to 3 and smaller than or equal to 12} in roster form
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- Given that X is a multiple of 3 such that it is ≥ 3 and ≤ 12.
- such multiples of 3 are :-
- 3,6,9,12
ADDITIONAL INFORMATION:-
- Empty set is a subset of every set
- Every set is a subset of itself
- improper subsets are always equal sets and vice versa
- No of subsets = 2^{no. of elements in that set}
- Power if set a set formed by all the subsets of that set.
Answered by
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Given :-
A= {x:x is a multiple of 3, x is greater than or equal to 3 and smaller than or equal to 12}.
To Find :-
The roster form of the given set .
Used Concepts :-
- In roster we have to find all the elements of a finite set and write them inside braces .
Solution :-
Let's start with the given that x is a multiple of 3 , x is greater than or equal to 3 and smaller than or equal to 12 .
If we have to find first three multiples of x then , Then it's multiple are x , 2x , 3x . In Easy language , The table of the given number .
Let , find the multiples of 3 , such that they are greater than or equal to 3 and less than or equal to 12 . They are as follows :-
3 , 6 , 9 , 12 .
Here , all conditions apply on the above elements of this question .
Hence , A = { 3 , 6 , 9 , 12 } .
Additional Information :-
For a set " A " .
- The empty / void / null set is subset of every set ( Including itself ) .
- The empty set is proper subset of every set ( Except Itself ) .
- If n ( A ) = m , them no. of subsets of A = 2^m .
- If n ( A ) = m , then no. of proper subsets of A = 2^m - 1 .
- If a subset of A is not proper , then it is improper subset .
- Let , Another set B , Then A is called the proper subset of B if and only all members of A are also members of B , but there is at least one element in B , that didn't belongs to A .
- Sets are always written in braces while ordered pairs in parentheses .
- The power set of A is the Set of all subsets of A .
- If n ( A ) = m ,then n { ( P ( A ) } = 2^m .
- Every set is subset of itself But not proper , because If no . of subsets of A are 2^m , then we have to minus 1 from the no. of subsets because A is not proper subset of A , then the formulae to find no. of proper subsets is 2^m - 1 , where n ( A ) = m .
- If n ( A ) = m , then total no. of unordered pairs of disjoint ( not overlapping ) subsets of A are 3^m- 1 /2! + 1.
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