Question

A={x/x is a prime number <10}
B={x/x is a odd number <7}
then find a quadratic polynomial in x whose zeroes are elements of
A Intersection B​

Answer 1

Answer:

x²-8x+15

Step-by-step explanation:

A={2,3,5,7}

B={1,3,5}

thus,A intersection B={3,5}

so,the required quadratic equation is

x²-(sum of roots)x+product of roots

=x²-(5+3)x+5*3

=x²-8x+15

Answer 2

Answer:

A={2,3,5,7}

B={1,3,5}

A intersection B ={3,5}

so, the zeroes of polynomial are 3,5;

sum of zeroes = 3+5=8

product of zeroes = 3*5=15

quadratic polynomial:

x^2-(sum of zeroes)x+(product of zeroes)=0

x^2-(8)x+15=0

x^2-8x+15=0

Hope this helps you

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