Math, asked by wcayush7617, 9 months ago

A=(x:x is an integer x square = 4) in roster form

Answers

Answered by pulakmath007
0

Roster form of A = { x : x is an integer , x² = 4 } is A = { - 2 , 2 }

Given :

The set A = { x : x is an integer , x² = 4 }

To find :

Roster form of A = { x : x is an integer , x² = 4 }

Concept :

Set :

A set is a well defined collection of distinct objects of our perception or of our thought to be conceived as a whole

Representation of Set :

A set can be represented in following ways

(i) Statement form method

(ii) Roster or tabular form method

(iii) Rule or set builder form method

Solution :

Step 1 of 2 :

Write down the given set

Here the given set is

A = { x : x is an integer , x² = 4 }

Step 2 of 2 :

Express in roster form

A = { x : x is an integer , x² = 4 }

Now we have ,

\displaystyle \sf{  {x}^{2} = 4  }

\displaystyle \sf{ \implies x =  \pm \sqrt{4} }

\displaystyle \sf{ \implies x =  \pm 2 }

\displaystyle \sf{ \implies x =  - 2,2}

We know that in roster form the elements are enclosed in curly brackets after separating them by commas

Hence the required roster form is given by A = { - 2 , 2 }

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Are there A and B equal set or disjoint set?

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Answered by vinod04jangid
0

Answer:

Roster form of A={ - 2 , 2 }

Step-by-step explanation:

Roster form of A = { x : x is an integer , x² = 4 } is A = { - 2 , 2 }

Given :The set A = { x : x is an integer , x² = 4 }

To find :Roster form of A = { x : x is an integer , x² = 4 }

Solution :

Step 1:-Write given set

A = { x : x is an integer , x² = 4 }

Step 2 :-A = { x : x is an integer , x² = 4 }

Now ,

x^{2}=4

⇒x=±\sqrt{4}

⇒x=±2

⇒x=-2,2

Hence the required roster form is given by A = { - 2 , 2 }

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