A = (x / x2-3x + 2 =0), B =[x] x is a digit in the number 121) & C= (1, 2)
Is A=B=C ? Justify
Don't spam
Please answer very fast
Answers
Answer:
Please check it
Mark it Brainlist
FOLLOW ME
THANK YOU
Step-by-step explanation:
ANSWER ::
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0So
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0So A = { 1 ,2 }
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0So A = { 1 ,2 } B = { x :, x is a digit in the number 121}
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0So A = { 1 ,2 } B = { x :, x is a digit in the number 121} = { 1, 2 }
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0So A = { 1 ,2 } B = { x :, x is a digit in the number 121} = { 1, 2 } C = { 1 ,2 }
ANSWER ::Since 1 & 2 are the zeros of x^2 - 3x+2 =0So A = { 1 ,2 } B = { x :, x is a digit in the number 121} = { 1, 2 } C = { 1 ,2 } So A = B = C = { 1 ,2 }
Answer:
ANSWER IN ATTACMENT SISO!!
