A = (x / x2-3x + 2 =0), B =[x] x is a digit in the number 121) & C= (1, 2)
Is A=B=C ? Justify
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no b=c but from a ,x^2-3x+2 cannot be zero as it is in the denominator. so it can't take the values 1 and 2. Hence a is different from the other two
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