Question

A= {x:x2

– 5x + 6 = 0}, B = {x:x2 – x – 6 = 0} then, find (i) A∪B (ii) A∩B

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Answer 1

$\huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

A = {x : (x)² - 5x - 6 = 0}

It can be written as ,

A = {6,-1}

and

B = {x : (x)² - x - 6 = 0}

It can be written as ,

B = {-3,2}

Thus ,

A∪B = {6,-1,-3,2}

and

A∩B = Φ

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