Question

a
x + y-1-
(2=
0
2
If the line
passing through the
intersection of
x - y +1=0 and 3x + y–5= 0
is perpendicular to
one of them, then the
value of a is​

Answer 1

Answer:

Given Lines

x−y+1=0------(1)

3x+y−5=0------(2)

from eq (1)

y=x+1

putting y in eq (2)

3x+x+1−5=0

4x=4

x=1

then y=2

Point of intersection be P(1,2)

now, slope of new lines ⊥ to given line would be m

1

=−1

(as it is -ve reciprocal)

m

2

=

3

1

Hence eq are

x+y=3 (m

1

=−1)

and

x−3y+5=0 (m

2

=

3

1

)

Answer 2

Answer:

answer

Explanation:

a=3. is this your answer