Question

A={(x,y):2x+4y=5 and x,y are counting numbers then |A| = what​

Answer 1

Answer:

I think I'm supposed to rewrite the equation in terms of (x−2y) and get a quadratic, but I'm not sure if I'm really supposed to do that. I tried completing the square with (x−1)2 and got: (x−1)2=6+4y but didn't know what to do after that. I can get the minimum value of 6+4y but that really doesn't help me at all. Please help me out!

Step-by-step explanation:

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Answer 2

Answer:

Let's call u=x−2y. Then you can rewrite your equation as

x2−2x−4x−u2=5

or

x2−4x+(2u−5)=0

You want u such that the equation above has a real solution, so

22−(2u−5)≥0

or