Question

(a^x)^y=a^x*a^y,find the value of x(y-1)-(y-1) ​

Answer 1

Step-by-step explanation:

(a^x)^y = a^xy

a^x*a^y = a^(x+y)

a^xy =a^(x+y)

xy = x+y

xy-(x+y)=0

x(y-1)-y+1 = xy -x-y+1= xy -(x+y)+1 = 0+1 =1