a(x²+1)-x(a²+1)
Find zeros
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hey mate
given equation
a(x²+1)-x(a²+1)=0
=>ax²+a - a²x-x=0
= >ax(x-a)-1(x-1)=0
=>(x-a)(ax-1)=0
=.>(x-a)= 0 ,or ax-1= 0
so,
x=a, and x= 1/a
thus:
zeroes of given equation will be
x= a, 1/a.
I hopes its help's u.
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@abhi.
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