A=x2-2xy+y2,B=3x2+4xy-y2 find 2a-3b
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Answer:
2a-3b
=2(x^2-2xy+y^2)-3(3x^2+5xy-y^2)
=2x^2-4xy+2y^2-9x^2-15xy+3y^2
=2x^2-9x^2-4xy-15xy+2y^2+3y^2
=5y^2-19xy-7x^2
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Step-by-step explanation:
A = (x^2-2xy+y^2). ×2 = 2x^2-4xy+2y^2
B = (3x^2+4xy-y^2). ×3 = 9x^2+12xy-3y^2
therefore, 2A-3B = -7x^2-16xy+5y^2
or, 2A-3B = 5y^2-16xy-7x^2
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