Question

a) xy(z - b²)
algebraic expression find the value of following products when x=1,y=1 and z=-1​

Answer 1

Answer:

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Step-by-step explanation:

X =1

1 x y(z-b²)

zy - zb²

y = 1

X x 1(z-b²)

zx - xb²

z = -1

X x y(-1 -b²)

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Answer 2

Answer:

Given :

x = 1, y = 1 and z = -1

Solution :

$a) \: \: xy(z - {b}^{2} )$

$\: \: 1 \times 1( - 1 - {b}^{2} )$

$\: \: 1( - 1 - {b}^{2} )$

$\: \: - (1 + {b}^{2} )$

$ans. \: \: - (1 + {b}^{2} )$

Hope it helps.