Question

a^y-z.b^z-x.c^x-y=1 [x+z=2y,b^2=ac]​

Answer 1

Answer:

ANSWER

Let a

x

=b

y

=c

z

=k .....( Given )

∵a

x

=k

⇒a=k

x

1

∵b

y

=k

⇒b=k

y

1

.....∵c

z

=k

⇒c=k

z

1

Given, b

2

=ac

Substituting values of a,b,c in above equation

(k

y

1

)

2

=k

x

1

×k

z

1

⇒k

y

2

=k

x

1

+

z

1

⇒

y

2

=

x

1

+

z

1

⇒

y

2

=

xz

x+z

⇒y=

x+z

2xz

Option (A) is correct.