A yacht,3 2⁄3 meters (mixed fraction) in height, is floating on water. If 1/6 of its height is underwater, What is the height of the yacht visible above the water( Please don't give inappropriate answer o they will be reported immediately
Answers
Answer:
55/18 or 3 1/18
Step-by-step explanation:
Total height = 3 2/3 = 11/3 (converting mixed fraction to improper fraction)
length under water = 1/6 of total = 1/6 x 11/3 = 11/18
length visible above water = 11/3 - 11/18 ( difference of total with length below water)
66/18 - 11/18 (LCM of denominator to subtract)
55/18 (improper fraction) or 3 1/18 (mixed fraction)
I hope it helps.
Answer:
Answer:
55/18 or 3 1/18
Step-by-step explanation:
Total height = 3 2/3 = 11/3 (converting mixed fraction to improper fraction)
length under water = 1/6 of total = 1/6 x 11/3 = 11/18
length visible above water = 11/3 - 11/18 ( difference of total with length below water)
66/18 - 11/18 (LCM of denominator to subtract)
55/18 (improper fraction) or 3 1/18 (mixed fraction)
Step-by-step explanation: